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IRE Flow6 White 2016 Karhu F200176 Women's Finnish Blue Shoe Running Calculate the total resistance of resistors in parallel with ease!

Inputs

(‎Ω)
(‎Ω)
 
 

Output

(Ω)

How to Calculate the Total Resistance of Resistors in Parallel 

 

Calculating the equivalent resistance (REQ) of resistors in parallel by hand can be tiresome. This tool was designed to help you quickly calculate equivalent resistance, whether you have two or ten resistors in parallel. To use it, just specify how many parallel resistors there are and the resistance value for each one. 

You can easily calculate the equivalent resistance when you have two identical resistors in parallel: it is half of the individual resistance. This is handy when you need a specific resistance value and don't have an appropriate part readily available. For example, if you know you need about 500 Ω to get the desired brightness out of an LED circuit, you can use two 1 kΩ resistors in parallel.

Keep in mind that the current through an individual resistor does not change when you add resistors in parallel, because adding resistors in parallel does not affect the voltage across the resistors' terminals. What changes is the total current delivered by the power supply, not the current through one particular resistor.    

Equations

1REQ=1R1+1R2+1R3+...+1RN

1REQ=1RToe WeenFashion Nappa Open Solid Sandals High Red Heels Women's Buckle q6qBxEwPp1+1RWhite IRE Flow6 Finnish Blue Running Women's 2016 Karhu Shoe F200176 2Finnish F200176 2016 Running Blue Karhu Flow6 Shoe Women's IRE White +1R3+...+1Blue F200176 Women's White Karhu Flow6 IRE 2016 Shoe Running Finnish RNVita PU Patent Bella Platform II Zari Women's Red zxOf4

When you have only two resistors in parallel: REQ=R1×R2R1+Blue IRE White Shoe F200176 Finnish Flow6 Women's 2016 Karhu Running R2

Applications

Resistors in series are equivalent to one resistor whose resistance is the sum of each individual resistor. Resistors in parallel, on the other hand, result in an equivalent resistance that is always lower than every individual resistor. If you think about it, this makes sense: If you apply a voltage across a resistor, a certain amount of current flows. If you add another resistor in parallel with the first one, you have essentially opened up a new channel through which more current can flow. No matter how large the second resistor is, the total current flowing from the power supply will be at least slightly higher than the current through the single resistor. And if the total current is higher, the overall resistance must be lower.

 

Further Reading

Comments

6 Comments


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Finnish Shoe Flow6 White 2016 Women's Blue Karhu F200176 Running IRE
  • mmikerosss 2017-09-15

    Women's Running F200176 Flow6 White Blue Karhu Shoe IRE 2016 Finnish Great tool, but there seems to be an error! If i am calculating, lets say the equivalent resistance of 6 resistors (5, 20, 15, 7, 10, 12) i should be getting 1.56ohms but instead i get 2.26ohms. Please try to fix the algorithm, otherwise great tool!

    • Robert Keim 2017-09-21

      I tried it with the same resistances and got 1.56 Ω, as expected. Are you still seeing 2.26 Ω?

      • mrrobin 2017-11-15

        I agree with you. I got same value.

  • jlhenager3 2018-03-20

    Just FYI, the parallel resistance calculator, and the form for joining AAC are completely broken if a Chrome or Firefox browser is being used. Both seem to be OK, if the browser being used is Micro$oft’s Internet Exploder. Oh, the joy of making javascript work across multiple browsers!
    Regardless, your tools are easy to use and handy.

  • pll_check 2018-05-13

    wrong calculator.. lol…
    5,10,2,1 show 0.56, equivalent resistor is greater than 1.